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2y^2+17y-8=0
a = 2; b = 17; c = -8;
Δ = b2-4ac
Δ = 172-4·2·(-8)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{353}}{2*2}=\frac{-17-\sqrt{353}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{353}}{2*2}=\frac{-17+\sqrt{353}}{4} $
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